MechSimulator

Induction Motor Simulator & AC Motor Virtual Lab

Free online induction motor simulator for three-phase and single-phase AC machines — watch the rotor slip behind the rotating field, plot the torque-slip characteristic, run no-load, blocked-rotor and load tests, extract the equivalent circuit, and compare star-delta against direct-on-line starting. Simulate · Explore · Practice · Quiz

MODE
UNITS
VIEW
Display Controls
GRAPH
Curve spans standstill to synchronous speed at the present settings

📚 Learning panels

Σ Live equations — values substituted from the current state
Power flow & losses
💡 What this machine is telling you

How to Use the Induction Motor Simulator

1. Pick a machine

The catalogue holds ten three-phase machines from 0.75 kW to 160 kW and four single-phase machines. Every nameplate you see — speed, current, power factor, efficiency — is solved from the equivalent circuit, not typed in. Start with the 5.5 kW, 400 V, 4-pole machine: it is the ordinary industrial workhorse and every other machine reads as a variation on it.

2. Load it up and watch the slip

Drag the Load torque slider. The rotating field keeps turning at synchronous speed while the rotor falls further behind — that growing gap is the slip, and it is what generates rotor current and therefore torque. Push past the breakdown torque and the machine stalls, because beyond that point more slip gives less torque.

3. Change the supply

Torque follows the square of the applied voltage, so a 10 per cent supply dip costs 19 per cent of the torque. Frequency changes the synchronous speed directly (Ns = 120f/P). Hold V/f constant and the whole curve slides sideways at almost constant height — that is exactly what a variable-frequency drive does.

4. Switch to the test bench

The VIEW switch above the graph swaps the canvas between two things. Machine is the cutaway with the live equivalent circuit — what the motor is. Test Bench is the laboratory: a three-phase supply through a variac and a star-delta starter, an instrument cluster, the motor bolted to a bedplate with a rotor-lock pin, and a rope-brake dynamometer — a water-cooled brake drum on the shaft with a rope over it, a spring balance on each end reading in kilograms, and a loading handwheel under each. That is the standard brake test on a three-phase induction motor, and the bench works it live: R = (D+d)/2, T = (S₁ − S₂) × 9.81 × R, P = 2πNT/60, η = P/(W₁+W₂).

Watch the two balances as you load the machine: their difference grows but their sum never changes. A rope is inextensible, so the tight side gains exactly what the slack side loses — and past the capstan limit S₁/S₂ = eμθ the rope slips and the rig says so.

Note there are two wattmeters, because that is how three-phase power is measured on a three-wire supply. Their sum is the total power, and their ratio gives the power factor. Run the no-load test and watch W₂ go negative — that is not a fault, it is what happens whenever the power factor falls below 0.5, and it is the classic thing this method is used to demonstrate.

5. Run a laboratory test

Load Test opens the picker. Each procedure runs as a timed sequence on the bench: the variac winds, the lock pin drops, the brake tightens, the needles swing and settle, and each reading is written onto the observation sheet as it is taken. A progress banner names the step you are watching, and you can cancel at any point. Nothing is scripted — every reading comes from the same solved model that drives the live readouts, so a test result and the simulator can never disagree.

6. Put a fault on the machine

A load test is a diagnostic. With every machine healthy all the procedures agree and you never find out what they are for, so the CONDITION selector puts a single realistic fault on the same nameplate — a stator winding fault, worn bearings, shorted laminations, an eccentric air gap, or broken rotor bars. Each one leaves its fingerprint on a different measurement:

Which test finds which fault — ratios against the sound machine, 5.5 kW example
FaultDC test (R₁)No-load interceptNo-load slopeNo-load currentBlocked rotor (R₂)
Stator winding fault1.90×1.00×1.01×1.00×1.00×
Worn bearings1.00×3.19×1.02×1.00×1.00×
Shorted laminations1.00×1.00×2.47×1.00×1.00×
Eccentric air gap1.00×1.00×0.99×1.37×0.97×
Broken rotor bars1.00×1.00×1.00×1.00×1.57×

Worn bearings and shorted laminations both raise the no-load power, and only running that test at several voltages separates them: friction does not care about voltage so it lands in the intercept, while core loss follows V² and lands in the slope. That is exactly why the standard asks for the multi-voltage version, and it is why no single test identifies a fault — the set of them does.

Diagnose reads the verdict back out of the measurements, never from the setting. Set a fault, run the tests, and see whether you would have caught it.

7. Read the graphs

Six views share the plot area. Torque-Slip is the characteristic itself with your operating point marked. Current & PF shows why a lightly loaded motor has such a poor power factor. Power Flow is the loss ledger from input to shaft. Efficiency shows the peak sitting below full load. Starting Methods compares torque against current for every starter. V/f Control overlays the curve at several frequencies.

8. Export

Test Report produces a printable laboratory report with the machine data, the readings taken, the calculations and the resulting characteristic — the document you would hand in. CSV exports the swept curve for plotting elsewhere.

Keyboard

Space pause or resume · adjust load · R reset · right-click the canvas for save, copy and reset.

Understanding the Induction Motor — a Free Interactive AC Motor Simulator

The three-phase induction motor turns roughly half the electrical energy generated on earth into mechanical work. It has no brushes, no commutator and no electrical connection to its rotor at all: the rotor current is induced, exactly as it is in the secondary of a transformer, which is why the machine is sometimes called a rotating transformer. This induction motor simulator solves the per-phase equivalent circuit in your browser, so every number on the screen — speed, slip, current, power factor, efficiency, torque — comes from one consistent solution rather than from a set of formulas that disagree at the edges.

Slip: why an induction motor can never reach synchronous speed

Three windings spaced 120° apart, carrying currents 120° apart in time, produce a magnetic field that rotates at the synchronous speed

Ns = 120 × f / P

where f is the supply frequency in hertz and P the number of poles. At 50 Hz a 2-pole machine gives 3000 rev/min, a 4-pole 1500, a 6-pole 1000 and an 8-pole 750. At 60 Hz those become 3600, 1800, 1200 and 900.

The rotor cannot turn at that speed. If it did, it would be moving with the field, no flux would cut the rotor bars, no EMF would be induced, no current would flow and no torque would be produced — the machine would immediately slow down. So the rotor always runs slightly behind, and the fractional lag is the slip:

s = (Ns − N) / Ns

Full-load slip is not a constant of nature; it falls steadily with machine size, because larger machines have proportionally lower rotor resistance. In the simulator's own catalogue:

Full-load performance by rating — solved from each machine's equivalent circuit, 400 V, 50 Hz, 4-pole unless noted
RatingFull-load speedSlipLine currentPower factorEfficiency
0.75 kW1404 rev/min6.4 %1.65 A0.7982.6 %
5.5 kW1450 rev/min3.3 %10.7 A0.8389.6 %
11 kW (2-pole)2920 rev/min2.7 %19.7 A0.8891.4 %
15 kW (8-pole)730 rev/min2.7 %30.5 A0.7891.0 %
75 kW1480 rev/min1.3 %131 A0.8795.0 %
160 kW (3.3 kV, 6-pole)989 rev/min1.1 %35.0 A0.8495.4 %

Two trends are worth pausing on. Efficiency climbs with size, from 82.6 per cent to over 95. And the 8-pole machine has a distinctly worse power factor than the 2-pole one at similar power, because a slow machine needs more magnetising current for the same output — a real design penalty that catches people out when they specify low-speed drives.

The torque-slip characteristic

Applying Thevenin's theorem to the equivalent circuit gives the torque at any slip:

T = (3 / ωs) × Vth² × (R₂/s) / [ (Rth + R₂/s)² + (Xth + X₂)² ]

The shape that falls out of this has three landmarks. Starting torque at s = 1. Breakdown torque, the maximum the machine can ever produce, at the slip

smaxT = R₂ / √(Rth² + (Xth + X₂)²)

and the near-straight working region between breakdown and synchronous speed, where the machine actually operates and where speed falls almost linearly with load.

Notice what is missing from the breakdown-torque expression: rotor resistance appears in the slip at which the peak occurs, but not in its height. Adding resistance to the rotor slides the peak towards standstill without changing how large it is. That single fact is the entire basis of wound-rotor starting, and you can watch it happen on the slip-ring machine in the simulator — the peak marches from 17 per cent slip out to 92 per cent while its height stays at 684 N·m.

Torque also follows the square of the applied voltage. A supply sagging to 90 per cent delivers only 81 per cent of the torque, which is why a heavily loaded motor on a weak supply can stall on a voltage dip that the lights barely register.

Why deep rotor bars exist: the skin effect that makes motors start

Here is a puzzle that a constant-parameter model cannot solve. Full-load slip on a 75 kW motor is about 1.3 per cent, which demands a very low rotor resistance. But low rotor resistance puts the breakdown torque close to synchronous speed and leaves almost nothing at standstill — on paper such a machine develops well under half its rated torque at start, and could not accelerate its own fan.

Real machines escape this by making the rotor resistance depend on speed. Rotor current frequency is s × f, so at standstill the bars carry full line frequency and the current crowds into the top of each bar; once the machine is up to speed the rotor frequency is only a hertz or two and the current spreads over the whole bar. For a rectangular bar the classical result gives the AC/DC resistance ratio as

kR = ξ (sinh 2ξ + sin 2ξ) / (cosh 2ξ − cos 2ξ), with ξ = h / δ

where h is the bar height and δ the skin depth. Because ξ scales with √(s f), a deep-bar rotor is high-resistance while starting and low-resistance while running — which is exactly what is wanted. This simulator models that effect explicitly, which is why its large machines start properly instead of collapsing at standstill, and it is also what the NEMA design letters physically describe.

NEMA MG 1 design classes — the rotor bar shape decides the character of the machine
DesignRotor constructionStarting torqueStarting currentFull-load slipTypical use
AShallow bar, low resistanceNormalHighLow, under 3 %Machine tools where inrush is not restricted
BDeeper bar, moderate skin effect1.5–2.5 × FLT5.5–7.5 × FLCUnder 5 %The general-purpose default: fans, pumps, compressors
CDouble cage2.0–2.5 × FLTNormalUnder 5 %Loaded conveyors, crushers, piston pumps
DShallow, high-resistance bar2.75 × FLT and aboveLow5–13 %Punch presses, shears, hoists — flywheel loads
WoundWire-wound rotor, slip ringsSet by external resistanceSet by external resistanceUnder 5 %Cranes, mills, high-inertia starts

No-load and blocked-rotor tests: finding the equivalent circuit

The equivalent circuit is not something you can measure directly. It is reconstructed from three terminal tests, and the no load and blocked rotor test pair is a standard laboratory exercise in every machines course.

The DC test gives stator resistance. Take care with the connection: applying DC across two terminals of a star winding puts two phases in series, so R₁ = V/2I, while on a delta winding it puts one phase in parallel with two in series, so R₁ = 1.5 V/I. Getting that factor wrong scales every copper-loss figure that follows.

The no-load test runs the machine uncoupled at rated voltage. Slip is almost zero, so R₂/s is enormous and the rotor branch is effectively open; what remains is the magnetising branch, the core loss, and friction and windage. Repeating the test at falling voltage and extrapolating the input power back to zero volts separates the last two, because core loss falls as V² while friction and windage does not change. In the simulator that extrapolation recovers the true friction-and-windage figure to within about two per cent.

The blocked-rotor test locks the shaft and raises the voltage until rated current flows. With s = 1 the rotor branch dominates and the magnetising branch can be neglected, giving rotor resistance and total leakage reactance. IEEE 112 specifies about 25 per cent of rated frequency for this test, and the reason is the skin effect described above: run it at full frequency on a deep-bar rotor and the rotor resistance reads far higher than its running value, describing a machine that does not exist above standstill. Run both versions in the simulator and compare the error — the standard exists for a measurable reason.

One caveat the textbooks are honest about and worth repeating: the split of leakage reactance between stator and rotor is not measurable. It is assigned from the design class, and that assumption is the largest single source of error in the whole procedure.

Starting an induction motor: why the inrush matters

At standstill the machine is a short-circuited transformer, and it draws five to seven times full-load current. On a small motor nobody notices. On a large one the volt-drop dims every light on the feeder, so supply authorities set limits and reduced-voltage starting becomes compulsory. Every reduced-voltage method obeys the same square law, because both torque and current scale with the square of the winding voltage.

Starting methods compared — all figures relative to direct-on-line
MethodLine currentStarting torqueNotes
Direct on line (DOL)100 %100 %Simplest and cheapest; harsh on the supply and the driven machine
Star-delta33 %33 %Only for delta-wound motors that can start unloaded; a current surge occurs at changeover
Autotransformer 80 % tap64 %64 %Tap selectable; more expensive, but torque per ampere is better than a series reactor
Autotransformer 65 % tap42 %42 %
Autotransformer 50 % tap25 %25 %
Rotor resistance (wound rotor only)ReducedIncreasedThe only method that raises torque while cutting current — hence its survival on cranes and mills

Star-delta deserves its own sentence, because the factor of three surprises people who expect √3. Reconnecting a delta winding into star drops each winding's voltage by √3, so winding current falls by √3. But in delta the line current was √3 times the winding current, whereas in star they are equal. The two factors multiply and the line current falls to a third. Torque, following voltage squared, also falls to a third. You can verify both on screen: the simulator computes them from the circuit rather than applying a rule of thumb.

Single-phase induction motors: the machine that cannot start itself

A single-phase winding does not produce a rotating field. It produces a pulsating one, which by simple trigonometry is identical to two fields of half amplitude rotating in opposite directions. The rotor sees slip s against the forward field and 2 − s against the backward one, and the net torque is the difference between what the two produce.

At standstill s = 1, so both fields present the rotor with exactly the same slip, the two torques are identical, and they cancel. A single-phase induction motor has precisely zero starting torque. Give the shaft a spin in either direction and it will run up in that direction, which is the classic lecture demonstration. In this simulator that zero is not a special case written into the code — it emerges from the algebra, and the verification suite asserts it.

Every practical single-phase motor therefore carries a second winding, displaced in space and fed with a current displaced in time. The rotating component of the field goes as Imain × Iaux × sinα, where α is the phase angle between the two currents, and the different ways of producing that angle define the motor types:

Single-phase starting methods — simulator figures at rated voltage
TypeHow the phase split is madeStarting torqueEfficiencyTypical application
Capacitor-startElectrolytic capacitor in the auxiliary winding, switched out at ~75 % speed3.5 × FLT~74 %Compressors, pumps, small machine tools
Split-phaseAuxiliary winding simply wound more resistive — about 25° of split1.8 × FLT~60 %Fans, small grinders, belt-driven blowers
PSC (permanent split capacitor)Small run capacitor stays in circuit permanently0.45 × FLT~59 %Ceiling fans, fan-coil units — anything starting unloaded
Shaded poleShorted copper ring drags the flux across part of each pole0.40 × FLT~27 %Microwave and refrigerator fans

The permanent split capacitor is the instructive case. Its starting torque is feeble not because its phase split is poor — the capacitor gives an excellent angle — but because a small run capacitor passes very little current. Keeping that capacitor in circuit while running is what gives the PSC its good power factor, around 0.80 against 0.60 for a split-phase machine of similar size.

Who uses this simulator?

Explore Related Simulators

Induction machines sit inside a family. The AC Generator Simulator covers the same rotating field from the generating side, with the EMF equation and alternator characteristics. The Star-Delta Connection Simulator works through the line and phase relationships that make star-delta starting give exactly one third. The Transformer Simulator shares this machine's equivalent circuit almost element for element — an induction motor really is a rotating transformer with a short-circuited secondary. And the DC Motor Simulator & Load Test Lab runs the same style of laboratory procedure on a DC machine, where speed control is easy and starting is the hard part — the mirror image of the trade-off here.